Question

A reaction has both ∆H and ∆S negative. The Feasibility of reaction​

Answer 1

When both delta H and delta S are negative, there can be two cases for, delta S(-ve) first, when temperature(T) increases then T(delta S) becomes more than delta H (from equation, delta G = delta H - T(delta S)). Thus, delta G becomes positive so, the reaction becomes non-spontaneous.

Second case, when delta S is negative, the temperature(T) decreases, therefore, T(delta S) becomes less than delta H. Thus, delta G becomes negative and the reaction becomes spontaneous.