Question

Given that triangles PQR and BAR, find the value of x and y​

Answer 1

Answer:

x value is 58°

Step-by-step explanation:

as Δpqr ~ Δbar,

∠Q = ∠A(∠x)

from angle sum property,

∠Q = 58°

∴∠X = 58°

Answer 2

Answer:

In ∆RAB

Angle R+ Angle A+Angle B=180°

54°+x+68°=180°

x=58°

Step-by-step explanation:

∆PQR~∆BAR

PQ/BA=QR/AR=PR/BR (by CPST)

2y/y+2=y+3/y

2y^2=(y+2) (y+3)

2y^2=y^2+3y+2y+6

y^2=5y+6

y^2-5y-6=0

y^2-3y-2y-6=0

y(y-3)-2(y-3)

y=3,2

PQ=AB=2y=y+2

so,y=2

Hope my answer is correct & it helps u!