Question

A reaction in equilibrium is represented by the
following equation -
2A(s) + 3B(g)<=>3C(g)+ D(g) + Q if the pressure
on the system is reduced to half of its original value:-
(1) The amounts of C and D decreases.
(2) The amounts of C and D increases
3) The amount of D decreases
(4) All the amounts remain constant​

Answer 1

A reaction in equilibrium is represented by the

following equation -

2A(s) + 3B(g)<=>3C(g)+ D(g) + Q if the pressure

on the system is reduced to half of its original value:-The amount of D decreases

Answer 2

Answer:

Option 2 is correct

Explanation:

Its because when pressure is high= Equilibrium shifts to Side with lesser moles and vice versa