Question

Find the HCF of 8x^3y^7 and 81x^5y^4


Plz ​

Answer 1

Answer:

Factorizing 4x2 - 9y2, we get

(2x)2 - (3y)2, by using the identities of a2 - b2.

= (2x + 3y) (2x - 3y)

Step-by-step explanation:

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Answer 2

Answer:

x^3 × y^4

HCF(8•x^3•y^7 and 81•x^5•y^4) =

x^3 × y^4

Step-by-step explanation:

Given,

8•x^3•y^7 and 81•x^5•y^4

Then, by the prime factorisation of :

8•x^3•y^7 = 2 × 2 × 2 × x × x × x × y × y × y × y × y × y × y

81•x^5•y^4 = 3 × 3 × 3 × 3 × x × x × x × x × x × y × y × y × y

We know that the least common factors are HCF of the numbers then,

HCF(8•x^3•y^7 and 81•x^5•y^4) = x × x × x × y × y × y × y = x^3 × y^4

Hence,

HCF(8•x^3•y^7 and 81•x^5•y^4) =

x^3 × y^4