one angle of the paralelogram is two third of the other .find the angle of the parallelogram
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Answer:
72°
Step-by-step explanation:
In a parallelogram ABCD,
Let ∠A be x and ∠B be 2x / 3
∴ ∠A + ∠B = 180°
⇒ x + 2x / 3 = 180°
⇒ 5x / 3 = 180°
⇒ x° = 180° × 3 / 5 = 108°
∠A = 108° , ∠B = 2 / 3 × 108° = 72°
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