A reaction is A + B⇌ C + D. Initially we
start with equal concentrations of A and B. At
equilibrium we find that the moles of C is two
times of A. What is the equilibrium constant of
the reaction?
(a) 1 (b) 1
4 2
(c) 4 (d) 2
Answers
Answered by
1
Answer:
Answer is (c) 4 is the correct answer
Answered by
1
(c) 4
Explanation:
A+B ⇌ C+D
At equilibrium C = 2A
x = 2(1-x)
3x = 2
Therefore x = 2/3
Initially: 1 1 0 0
Equilibrium:1-x 1-x x x
Finally: 1-2/3 1-2/3 2/3 2/3
Kc = [C].[D] / [A].[B] = [2/3 * 2/3] / [1/3 * 1/3] = 2 * 2 = 4
Option C is the answer.
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