Chemistry, asked by yogitarajesh8826, 9 months ago

The equilibrium which remains unaffected by pressure change is
(a) N₂ (g) +O₂ (g) ⇌ 2NO(g)
(b) 2SO₂ (g) +O₂ (g) ⇌ 2SO₃(g)
(c) 2O₃(g) ⇌ 3O₂ (g)
(d) 2NO₂ (g) ⇌ N₂O₄ (g)

Answers

Answered by Anonymous
0

Answer :- (b) 2SO₂ (g) +O₂ (g) ⇌ 2SO₃(g)

Answered by Rameshjangid
0

Answer:

The equilibrium which remains unaffected by pressure change is N₂ (g) +O₂ (g) ⇌ 2NO(g).

Explanation:

Step 1: A pressure (or volume) change does not impact the position of equilibrium if the total number of moles of the gases involved in the reaction does not change; in other words, Q is unaffected by the change in volume (or pressure).

Step 2: According to Le Chatelier's principle, an equilibrium is shifted to the reaction's side with the fewest moles of gas when pressure is increased, and to the reaction's side with the most moles of gas when pressure is decreased.

Step 3:The following equilibria  remains unaffected by pressure change :  

(A) $\mathrm{N}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})$.

For these equilibria, the total number of moles of gaseous reactants are equal to the total number of moles of gaseous products or Δn=0.

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