a reaction is completed from 100%. to 80% in 20 sec what will be rate
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For a first order reaction, t1/2 = 0.693k k = 0.69325 = 0.028 min-1 Now using first order eqution, K = 2.303t log [R° ] [ R ] t = 2.3030.028log [R0 ]0.2
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