Question

A reaction is of second order with respect to a reactant. How will the rate of reaction change if concentration of reactant is reduced to half

Answer 1

$ASSALAMUALAIKUM$

Let the reaction is A --> Product
Rate = k[A]2

(I) If conc. of A is doubled
R’ = K[2A]2 = 4K[A]2 = 4R
So rate of reaction will increae four times.
(ii) If conc, of reactants is reduced to half
R’ = K[1/2A]2= 1/4K[A]2= R/4
Rate of reaction will reduced to one fourth of the initial rate.

$INSHAALLAH it will help you!$

$\mathbb{\huge{A.K.}}$

Answer 2

Let the reaction is A --> Product

Rate = k[A]2

(I) If conc. of A is doubled

R’ = K[2A]2 = 4K[A]2 = 4R

So rate of reaction will increae four times.

(ii) If conc, of reactants is reduced to half

R’ = K[1/2A]2= 1/4K[A]2= R/4

Rate of reaction will reduced to one fourth of the initial rate.