Question

A reaction taking place in a container with a piston-cylinder assembly at constan
temperature produces a gas, and the volume increases from 125 mL to 652_mL against an
external pressure of 988 torr. Calculate the work done (in J; 1 atm L 5101.3 J).​

Answer 1

Answer:

60.4 J

Explanation:

The work done of a gas is given by :

W = p( Vf - Vi )

where , p is the gas pressure

Vf is the final volume of the gas

Vi is the initial volume

Converting all the quantities into S.I units :

p = 860 torr . 1.014.10^5 pa = 1.146 . 10^5 Pa

760 torr

Vi = 127 ml = 0.127 l = 0.127 dm^3 = 0.127 . 10^-3 m^2

Vf = 654 ml = 0.654 l = 0.654 dm^3 = 0.654 . 10^-3 m^2

So , the Work done is

W = ( 1.146 . 10^5 Pa ) ( 0.654 . 10^-3 m^2 - 0.127 . 10^-3 m^2 ) = 60.5 J

Hope this answer will help u !!