Question

A real estate agent purchased a house for 25,70,000 and sold at a loss of 22%. Find:(i) his actual loss in rupees. (ii) selling price.

Answer 1

Answer:

1) loss= 22%

25,70,000×22%

=5,65,400 loss

2) selling price = purchased value - loss

=25,70,000 - 5,65,400

= 20,046,00

Answer 2

First we find 22% of 25,70,000

=22/100*25,70,000

= rs 5,65,400(his loss in rupees)

2.sp=(100-l%)/100*cp

=(100-22)/100*25,70,000

=20,04,600 rs