Question

A real-valued function f satisfies the relation
f(
x6) = f(2xy + 3) +35 (x + y) – 3f (y) + 6y, for all real numbers x and y.
Then the value of f(8) is​

Answer 1

Step-by-step explanation:

real-valued function f satisfies the relation

x6) = f(2xy + 3) +35 (x + y) – 3f (y) + 6y, for all real numbers