A reckless drunk is playing with a gun in an airplane that is going directly east at 500km/hr. The drunk shoots the gun straight up at the ceiling of the plane. The bullet leaves the gun at a speed of 1000km/hr. Relative to an observer on earth , what angle does the bullet make with the vertical?
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Answered by
117
Horizontal component of the bullet : 500 km/hr
Vertical component = 1000 kmph
Resultant velocity of the bullet: √[500² + 1000²] = 500 √5 kmph
Angle made by the velocity of the bullet with vertical = Ф
TanФ = 500/1000 = 1/2
Angle = Ф = Tan⁻¹ 1/2 = 26.56°
Vertical component = 1000 kmph
Resultant velocity of the bullet: √[500² + 1000²] = 500 √5 kmph
Angle made by the velocity of the bullet with vertical = Ф
TanФ = 500/1000 = 1/2
Angle = Ф = Tan⁻¹ 1/2 = 26.56°
Answered by
22
Answer:
Vb=1000km/h
Vp=500km/h
tan theeta = P/B
500/1000=1/2
tantheeta=1/2
Theeta =1/2tan^-1
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