a rectangle ABCD is inscribed in a circle with diameter lying along the line 3 X 4 Y = 7 if A and B are the points (-6, 5) and (4, 5) respectively find the equation of circle
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r2=PM2+AM2
r2=42+52
r2=16+25
r=41−−√
equation of circle
(x+!)2+(y−3)2=4
Area of squarre=AB⋅AD
=AB⋅2PM
=2⋅4⋅10
=80unit2.
Step-by-step explanation:
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