Question

a rectangle and a square have the same perimeter of a 80m if the length of the rectangle is 6 m more than the breadth find area of rectangle

Answer 1

suppose width of rectangle is b.
given
length l=6m
and perimeter of rectangle=80m
then...
the perimeter of rectangle =2(length+width)
2(l+b)=80
2(6+b)=80
12+2b=80
2b=80-12
2b=68
b=68/2
b=34m

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Assumption

Breadth of rectangle = p

Hence,

Length = (p + 6)

As we know that,

${\boxed{\sf\:{Perimeter\;of\;rectangle\;= 2(l\;+\;b)}}}$

Hence,

80 = 2(p + 6 + p)

80 = 2(2p + 6)

80 = 4p + 12

4p = 80 - 12

4p = 68

$\tt{\rightarrow p=\dfrac{68}{4}}$

p = 17

Now,

Dimension :-

Breadth = p = 17

Also

Length = p + 6 = 17 + 6 = 23 m

Now,

Area of rectangle = l × b

= 23 × 17

= 391 m²

$\Large{\boxed{\sf\:{Area\;of\;Rectangle=391 m^2}}}$