A rectangle and a triangle has equal area the length and breadth of the rectangle are 18cm×18cm find the height of the triangle of its base is 32 cm
Answers
Answer:
Height of the triangle is 20.25 cm.
Step-by-step explanation:
From the properties of quadrilaterals & triangles :
- Area of rectangle = length x breadth
- Area of ∆ = 1 / 2 x height x base
Here,
Area of rectangle = Area of triangle
= > Length of rectangle x breadth of rectangle = 1 / 2 x base of triangle x height of triangle ( perpendicular on base from the opposing angle )
= > 18 cm x 18 cm = 1 / 2 x 32 cm x height( of ∆ )
= > 18 cm x 18 cm = 16 cm x height
= > 18 cm x 18 cm / ( 16 cm ) = height
= > 9 x 9 / 4 cm = height
= > 20.25 cm = height
Hence height of the triangle is 20.25 cm.
Answer:
Height of ∆ = 20.25 cm.
Step-by-step explanation:
As we know that,
[ Area of rectangle = Length × Breadth ]
[ Area of triangle = 1/2 × Base × Height ]
According to the question,
=> Area of rectangle = Area of triangle
=> Length × Breadth = 1/2 × Base × Height
=> 18cm × 18cm = 1/2 × 32cm × Height
=> 18cm × 18cm = 16cm × Height
=> 18cm × 18cm / 16cm = Height
=> 9cm × 9cm / 4cm = Height
=> 20.25 cm = Height
[ .°. Height of ∆ = 20.25 cm ]