Math, asked by durgagupta658, 11 months ago

A rectangle and a triangle has equal area the length and breadth of the rectangle are 18cm×18cm find the height of the triangle of its base is 32 cm

Answers

Answered by abhi569
28

Answer:

Height of the triangle is 20.25 cm.

Step-by-step explanation:

From the properties of quadrilaterals & triangles :

  • Area of rectangle = length x breadth
  • Area of ∆ = 1 / 2 x height x base

Here,

Area of rectangle = Area of triangle

= > Length of rectangle x breadth of rectangle = 1 / 2 x base of triangle x height of triangle ( perpendicular on base from the opposing angle )

= > 18 cm x 18 cm = 1 / 2 x 32 cm x height( of ∆ )

= > 18 cm x 18 cm = 16 cm x height

= > 18 cm x 18 cm / ( 16 cm ) = height

= > 9 x 9 / 4 cm = height

= > 20.25 cm = height

Hence height of the triangle is 20.25 cm.

Answered by BrainlyCoder
43

Answer:

Height of ∆ = 20.25 cm.

Step-by-step explanation:

As we know that,

[ Area of rectangle = Length × Breadth ]

[ Area of triangle = 1/2 × Base × Height ]

According to the question,

=> Area of rectangle = Area of triangle

=> Length × Breadth = 1/2 × Base × Height

=> 18cm × 18cm = 1/2 × 32cm × Height

=> 18cm × 18cm = 16cm × Height

=> 18cm × 18cm / 16cm = Height

=> 9cm × 9cm / 4cm = Height

=> 20.25 cm = Height

[ .°. Height of ∆ = 20.25 cm ]

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