Question

find the weight of a hollow cylinder lead pipe 28 cm long and 1/2 cm thick its internal diameter is 8 cm weight of 1 cm cube of lead is 11.4 g

Answer 1

Answer:

Step-by-step explanation:

Volume of lead used=volume of cylinder(with outer diameter) -volume of cylinder(with inner diameter)

= π(8.5)^2*28-π*(8)^2*28

=π*28(8.5^2-8^2)

=28π(8.25)

=726cm^3

Weight of vessel=726*11.4=8276.4g