find the weight of a hollow cylinder lead pipe 28 cm long and 1/2 cm thick its internal diameter is 8 cm weight of 1 cm cube of lead is 11.4 g
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Step-by-step explanation:
Volume of lead used=volume of cylinder(with outer diameter) -volume of cylinder(with inner diameter)
= π(8.5)^2*28-π*(8)^2*28
=π*28(8.5^2-8^2)
=28π(8.25)
=726cm^3
Weight of vessel=726*11.4=8276.4g
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