Question

A rectangle formed by bonding a piece of wire whose length is 56 cm .If the rectangle has an area of 171cm2 . Find it's dimensions​

Answer 1

Answer:

l×b = 56 ×b = 171

b = 171 ÷56 = 3.053cm.

Answer#

Answer 2

Answer:

l=19

b=9

or

l=9

b=19

Step-by-step explanation:

Perimeter=2(l+b)

56cm=2(l+b)

l+b=28

b=28-l

Area = 171 sqcm

l*b=171

l(28-1)=171

28l-$l^{2}$=171

$l^{2}$-28l+171=0

$l^{2}$-19l-9l+171=0

l(l-19)-9(l-19)=0

(l-19)(l-9)=0

(l-19)=0             (l-9)=0

l=19                    l=9

b=28-l                 b=28-l

b=28-19               b=28-9

b=9                       b=19