a rectangle gate is 3 metre wide and has a 5 metre diagonal how high is the gate
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Answered by
15
Heyy mate ❤✌✌❤
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️
Breadth of the gate = 3m
Diagonal of the gate = 5m
By Pythagoras theorem,
Diagonal^2 = Height^2 + Breadth^2
=> 5^2 = x^2 + 3^2
=> x^2 = 25 - 9
=> x^2 = 16
=> x = 4m.
So, The height of the gate is 4m.
Here's your Answer....
⤵️⤵️⤵️⤵️⤵️⤵️
Breadth of the gate = 3m
Diagonal of the gate = 5m
By Pythagoras theorem,
Diagonal^2 = Height^2 + Breadth^2
=> 5^2 = x^2 + 3^2
=> x^2 = 25 - 9
=> x^2 = 16
=> x = 4m.
So, The height of the gate is 4m.
shrikanth46:
no key answer is 14
Answered by
9
HEY Buddy....!! here is ur answer
Given that : Breadth of rectangular gate = 3 m
and has a 5 meter diagonal.
Then, by Pythagoras theoram :
(Diagonal)² = (Height)²+(Breadth)²
=> (5)² = H² + (3)²
=> 25 = H² + 9
=> H² = 16
=> H = 4 m
So, the height will be 4 m.
I hope it will be helpful for you...!!
THANK YOU ✌️✌️
Given that : Breadth of rectangular gate = 3 m
and has a 5 meter diagonal.
Then, by Pythagoras theoram :
(Diagonal)² = (Height)²+(Breadth)²
=> (5)² = H² + (3)²
=> 25 = H² + 9
=> H² = 16
=> H = 4 m
So, the height will be 4 m.
I hope it will be helpful for you...!!
THANK YOU ✌️✌️
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