a rectangle has a perimeter of 10 cm if it's sides are doubled by how much time will it's perimeter increase
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Answer:
Let sides be l,b
2(l+b)=10
Now they gave the new sides are 2l,2b
2(2l+2b)=2(10)=20
Therefore percent increase=(20–10/10)*100=100%
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Side of a square = 10 cm
Perimeter of square = 4 × side
= 4 x 10 cm
= 40 cm
Side of square after doubling the length = 20 cm
Perimeter of new square = 4 × new side
= 4 × 20 cm
= 80 cm
Thus, the new perimeter will also be doubled, if the side of the square is doubled
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