Question

A rectangle has a perimeter of 96 cm. its length is twice its breadth. Find its dimensions.​

Answer 1

Answer:-

• Let Breadth=x
• Length=2x

ATQ

$\\ \sf\longmapsto Perimeter=96cm$

$\\ \sf\longmapsto 2(Length+Breadth)=96$

$\\ \sf\longmapsto 2(x+2x)=96$

$\\ \sf\longmapsto 2(3x)=96$

$\\ \sf\longmapsto 6x=96$

$\\ \sf\longmapsto x=\dfrac{96}{6}$

$\\ \sf\longmapsto x=16$

$\\ \sf\longmapsto 2x=2(16)=32$

• Length=32cm
• Breadth=16cm

Answer 2

Answer:

$perimeter = 96cm$

$half \: perimeter = \frac{96}{2} = 48cm$

$breadth = x$

$length = 2x$

$x + 2x = 48$

$3x = 48$

$x = 16$

$length = 32cm$

$breadth = 16cm$

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