A rectangle has a width that is 7 centimeters less than its length, and its area is 330 square centimeters. What are the dimensions of the rectangle?
Answers
Let length of rectangle be x cm.
A rectangle has a width that is 7 centimeters less than its length.
Width = (x - 7) cm
Area of rectangle = 330 cm²
Area of rectangle = length × breadth
Substitute the known values in above formula
=> 330 = x(x - 7)
=> 330 = x² - 7x
=> x² - 7x - 330 = 0
=> x² - 22x + 15x - 330 = 0
=> x(x - 22) +15(x - 22) = 0
=> (x - 22) (x + 15) = 0
=> x = 22, -15
[-15 neglected as length can't be negative]
So,
Length of rectangle = 22 cm
Breadth of rectangle = 22 - 7
=> 15 cm
•°• Dimensions of the rectangle are 22 and 15 cm respectively.
Length = 22 cm
Breadth (width) = 15 cm
Given :
- A rectangle has a width that is 7 centimeters less than its length
- Area of rectangle = 330 sq. cm
To find :
- Dimensions of the rectangle
- Length
- Breadth (width)
Solution :
Let the length of the rectangle be x cm.
- Width is 7 centimeters less than its length
•°• Width of rectangle = (x - 7) cm
We have the area of the rectangle. So using the formula for area of a rectangle we can solve the question further.
Block in the values,
Solve the quadratic equation so formed by factorization method,
x = - 15 is neglected since length cannot be negative.
•°• Length = x = 22 cm
Breadth = x - 7 = 22 - 7 = 15 cm
Dimensions :-
- Length = 22 cm
- Breadth (width) = 15 cm