A rectangle has an area of 25cm sqaured. If each side has its length doubled. What is the new area?
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L = Length
B = Breadth
Area of rectangle = L×B
![LB =25 \: cm ^{2} \: \: \: \: ....(1) \\ making \: length \: double \: = 2L \\ breadth = B \\ new \: area \: = 2L \times B \\ = 2LB \\ = 2(25 \: cm^{2} ) \: \: \: \: \: \:[from \: (1)]\\ = 50cm ^{2}](https://tex.z-dn.net/?f=LB+%3D25+%5C%3A+cm+%5E%7B2%7D+++%5C%3A++%5C%3A++%5C%3A++%5C%3A+....%281%29+%5C%5C+making+%5C%3A+length+%5C%3A+double+%5C%3A++%3D+2L+%5C%5C+breadth+%3D+B++%5C%5C+new+%5C%3A+area+%5C%3A++%3D+2L+%5Ctimes+B+++%5C%5C+%3D+2LB++%5C%5C+%3D++2%2825+%5C%3A+cm%5E%7B2%7D+%29+%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A%5Bfrom+%5C%3A+%281%29%5D%5C%5C+%3D++50cm+%5E%7B2%7D+ "LB =25 \: cm ^{2} \: \: \: \: ....(1) \\ making \: length \: double \: = 2L \\ breadth = B \\ new \: area \: = 2L \times B \\ = 2LB \\ = 2(25 \: cm^{2} ) \: \: \: \: \: \:[from \: (1)]\\ = 50cm ^{2}")
B = Breadth
Area of rectangle = L×B
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