Question

A rectangle has an area of 420m2. One of the sides is 5m in length. Work out the perimeter of the rectangle.

Answer 1

Answer:

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to inform the students about the same. You are Divya/Dewan.

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Answer 2

Answer:

$\huge{\boxed{\rm{\red{perimeter=178 m}}}}$

Step-by-step explanation:

Given :-

A rectangle has an area of 420m²

One of the sides is 5m in length.

To find:-

Find the perimeter of the rectangle.

Solution:-

Length of the rectangle (l)=5m

Area of the rectangle(A)=420m²

Let the breadth of the rectangle be 'b' m

Area of the rectangle =lb sq.units

=>A=5×b=5b sq.m

According to the problem

Area of the rectangle =420m²

=>5b=420

=>b=420/5

=>b=84 m

Breadth=84 m

Now,

Perimeter of the rectangle =2(l+b) units

=>P=2(5+84) m

=>P=2(89) m

=>P=178 m

Perimeter =178 m

Answer:-

Perimeter of the rectangle =178 m

Used formulae:-

If length and breadth of the rectangle are "l" and "b"units then

(1) Area of the rectangle=lb sq.units

(2)Perimeter of the rectangle=2(l+b) units