Question

A rectangle has same area as that of a square of side 10 metre if the breadth of the rectangle is 8 M find the perimeter of the rectangle​

Answer 1

Answer:

Area of rectangle= area of square

Area of square= 100 cm² (side* side, i.e., 10*10)

Area of rectangle

length*8= 100

Length of rectangle= 100/8

= 12.5 cm

Now, perimeter= 2(12.5+8)

=2*20.5

= 41 cm.

Answer 2

★ Given :-

• A rectangle has same Area as that of a Square of Side 10 m .
• Breadth of the rectangle is 8 m .

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★ To Find :-

• Perimeter of the Rectangle = ?

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★ Solution :-

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∓ Here, it is given that, A rectangle has same Area as that of a Square of Side 10 metre . Breadth of the rectangle is 8 meter . And, we have to find the Perimeter of the Rectangle .

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• Now, let's solve step by step -----

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◆ First, we will calculate Lenght :-

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$\pmb{ \dag \: \sf{Area \: of \: Rectangle = Area \: of \: Square}} \\ \\ \dashrightarrow \: \sf{Lenght \times Breadth = Side \times Side} \\ \\ \dashrightarrow \: \sf{Lenght \times 8 = 10 \times 10} \\ \\ \dashrightarrow \: \sf{Lenght = 10 \times \frac{10}{8} } \\ \\ \dashrightarrow \: \sf{Lenght = \frac{100}{8} } \\ \\ \dashrightarrow \: \sf{Lenght = \frac{25}{2} }$

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◆ Now, we will calculate Perimeter :-

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$\pmb{\sf{ \dag \: Perimeter \: of \: Rectangle =2 \: [ \: L + B \: ]}} \\ \\ \dashrightarrow \: \sf{Perimeter = 2 \times \bigg[ \: \: \frac{25}{2} + 8 \: \: \bigg]} \\ \\ \dashrightarrow \: \sf{Perimeter = 2 \times \bigg[ \: \frac{25}{2} \: \bigg] + 2 \times \big[ \: 8 \: \big] } \\ \\ \dashrightarrow \: \sf{Perimeter = \bigg[ \: \frac{50}{2 } \: \bigg]+ 16 } \\ \\ \dashrightarrow \: \sf{Perimeter = 25 + 16} \\ \\ \dashrightarrow \: \sf{Perimeter = 41 }$

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★ Hence :-

• Perimeter of Rectangle = 41 meter .

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