A rectangle has side (3+√2) metre and (5-√2).Find the area of the rectangle and length of its diagonal
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Given
Sides of a rectangle = (3+√2), (5-√2)
Area = Length * Breadth
= (3+√2) * (5-√2)
= 3 (5-√2) + √2* (5-√2)
=15-3√2+5√2-2
=13+2√2m²
Diagonal=√length²+breadth²
=√ (3+√2)²+(5-√2)²
=√ 9+2+6√2+25+2-10√2
=√(38-4√2)
Sides of a rectangle = (3+√2), (5-√2)
Area = Length * Breadth
= (3+√2) * (5-√2)
= 3 (5-√2) + √2* (5-√2)
=15-3√2+5√2-2
=13+2√2m²
Diagonal=√length²+breadth²
=√ (3+√2)²+(5-√2)²
=√ 9+2+6√2+25+2-10√2
=√(38-4√2)
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