What is the angle made by vector A i j = 2ˆ + 2 ˆ r with x – axis?
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Vector A= 2î + 2j
X axis= î
Dot product
(2î + 2j) . î
= 2
A.X= |A||X|cosθ
|A|= 2 root2
|X|= 1
Thus cosθ= 2/2root2
cosθ= 1/root2
Hence θ= 45°
X axis= î
Dot product
(2î + 2j) . î
= 2
A.X= |A||X|cosθ
|A|= 2 root2
|X|= 1
Thus cosθ= 2/2root2
cosθ= 1/root2
Hence θ= 45°
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