Question

A rectangle has sides of 6 and 8. What is the dimension of the diagonals?​

Answer 1

Answer:

$\sqrt{ {8}^{2} + {6}^{2} } \\ = \sqrt{64 + 32} \\ = \sqrt{100 } \\ = 10 \: units$

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Answer 2

l=8cm

b=6cm

diagonal:by Pythagoras theorem

AB²=BC²+AC²

d²=8²+6²

=64+36

d²=100

d=√100=√10×10

d=10cm

diagonal of the rectangal=10cm