A rectangle has the breadth and length be if the both is decreased by 20% and the length is increased by 10% then what is the area of new rectangle percentage comparative
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Area= Length*Breadth, A= a.b,
Let x and y be the scale ( increase / decrease) factors,
Scaled area A’= (a+a.x)(b+b.y) = a.b + a.b(x.y+x + y)= A+ A ( x.y+x+y)
So, the factor of change in area P = x.y+ x +y
In the given case x =0 .2 , y= - 0.2, so P= -0.04+0.2–0.2 = -0.04, which translates ( P*100) to a 4% decrease in area
Let x and y be the scale ( increase / decrease) factors,
Scaled area A’= (a+a.x)(b+b.y) = a.b + a.b(x.y+x + y)= A+ A ( x.y+x+y)
So, the factor of change in area P = x.y+ x +y
In the given case x =0 .2 , y= - 0.2, so P= -0.04+0.2–0.2 = -0.04, which translates ( P*100) to a 4% decrease in area
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