a rectangle is 10 CM long and 8cm wide.when each side of the rectangle is increased by x CM,its perimeter is doubled. find the equation in x and hence find the area of the new rectangle
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Answer:
Initial perimeter =2 (10+8)
Final sides=10+x,8+x
Final perimeter =2 (10+x+8+x)=2(18+2x)
A.T.Q
2×Inital perimeter = Final perimeter
=> 2(18×2)=2(18+2x)
=>36=18+2x
=> x= 9
New sides were 19,17
Hence, new area is 19×17= 323
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