Question

A rectangle is 10 times as long as it is wide. Its perimeter is 88 cm. What are the dimensions (width and length) of the rectangle?

Answer 1

Answer:

40 cm ; 4 cm.

Step-by-step explanation:

Let the width of the rectangle be a. So, as length is 10 times of the width it should be 10 times of a, length of the rectangle is 10a.

  Here,

      Perimeter = 88 cm

 2( length + width ) = 88 cm

   length + width = 44 cm

   10a + a = 44 cm

   11a = 44 cm

   a = 4 cm

    Thus,

           Width of the rectangle is 4 cm and length is 10a or 10( 4 cm ) or 40 cm.

Answer 2

$here \: is \: your \: answer \\ let \: the \: breadth \: be \: x \\ now \: perimeter \: of \: rectangle \: = 2(l + b) \\ now \: length \: = 10x \: and \: breadth \: = x \\ so \\ = 2(10x + x) = 88 \\ = 20x + 2x = 88 \\ 22x = 88 \\ = x = \frac{88}{22} \\ x = 4 \\ hence \: breadth \: (width) = 4 \: and \: length \: = 10 \times 4 = 40 \\ hope \: it \: helped \\ plz \: mark \: as \: brianliest \\ \\ \\ \\ \\ stay \: home \: stay \: safe$