Question

A rectangle is 16 m by 9 m. Find the side of a square whose area equals the area
of the rectangle. By how much does the perimeter of the rectangle exceed the
perimeter of the square? Please write in formula

Answer 1

Dimension of rectangle = 16 m×9m

Area = 144 m²

Given,

area of rectangle = area of square

then, area of square = 144 m²

Area of square = a²

144 = a²

a = √(144)

a = 12

Perimeter of square = 4 × side

= 4×12

= 48 m

perimeter of rectangle = 2(l+b)

=> 2(16+9) m

=> 32 + 18 m

=> 50m

Perimeter of rectangle exceeds the perimeter of square by 2m

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Answer 2

Area of rectangle = (16 × 9) m2 = 144 m2

Given condition,

Area of square = Area of rectangle

∴ (Side)2 = 144

Side = √144 = 12 m

Now,

Perimeter of square = 4 × side = 4 × 12 = 48 m

Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m

Hence, difference in their perimeters = 50 – 48 = 2 m