Question

A rectangle is 16m and 9m. Find the side of square whose narea is equal to the area of rectangle by how much does the perimeter of rectangle exceeds the perimeter of the square.? ​

Answer 1

Answer:

Side of square = 12m

Perimeter of rectangle exceeds that of square by 2m

Step-by-step explanation:

Area of rectangle = length x breadth = 16 x 9 = 144m^2

So, the area of square is also 144m^2.

Since area of square = s^2,

side of square = √144 = 12m.

Now, perimeter of rectangle = 2 x (length + breadth) = 2 x (16 + 9) = 50m.

Perimeter of square = 4 x side = 4 x 12 = 48m.

Thus, the perimeter of the rectangle exceeds that of the square by 2m.

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