Question

A rectangle is 16m by 9m. Find a side of the square whose area is rials the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square?

Answer 1

Answer: 2cm

Step-by-step explanation:

area of the rectangle= 16*9

thus area of the square = 16*9

perimeter of the square= √(16*9)*4=48 cm

perimeter of rectangle- perimeter of square= 50-48 = 2cm