Math, asked by deepakgupta1725, 5 months ago

A rectangle is 22 m long and 12 m wide. From its four corners quadrants of radius 2.5 m have been cut. Find the area of the remaining part.

Answers

Answered by mathdude500
18

Question :-

  • A rectangle is 22 m long and 12 m wide. From its four corners quadrants of radius 2.5 m have been cut. Find the area of the remaining part.

\bf\large \underbrace\red{Answer:}

Given :-

  • A rectangle is 22 m long and 12 m wide.
  • From its four corners quadrants of radius 2.5 m have been cut.

To Find :-

  • The area of the remaining part.

Formulas :-

\bf \:\boxed{Area\:of\:Rectangle=l \times b}

where,

  • l = Length of rectangle
  • b = Breadth of rectangle

{{ \boxed{\large{\bold{Area_{(Quadrant \: of \: Circle)}\:\ = \: \dfrac{1}{4} \pi r^2  }}}}} \:

where,

  • r = Radius of circle.

Solution :-

Step 1.

Length of rectangle = 22 m

Breadth of rectangle = 12 m

⇛ Area of rectangle = 22 × 12 = 264 m²

Step 2.

Radius of circle = 2.5 m

\bf \:Area  \: of \:  quadrant  = \dfrac{1}{4} \pi \:  {r}^{2}

\bf\implies \:\dfrac{1}{4}  \times \dfrac{22}{7}  \times 2.5 \times 25

\bf\implies \:4.91 \:  {m}^{2}

Area of 4 quadrants = 4 × 4.91 = 19.64 m²

Now,

Remaining area = Area of rectangle - Area of 4 quadrants

⇛ Remaining Area = 264 - 19.64 = 244. 36 m²

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