A rectangle is surrounded by two sets of congruent trapeziums as shown in the adjacent figure. Find the area covered by each of these trapeziums.
Answers
24.05 cm² & 6.93 cm²are ares of individual trapezium & 61.96 cm² is total area covered by trapeziums
Step-by-step explanation:
if We need to get area covered by all trapezium
then Area = 20.6 * 4.6 - 16.4 * 2
= 94.76 - 32.8
= 61.96 cm²
if We found area of trapezium one by one
Sizes of two Trapezium are
16.4 & 20.6 cm parallel Side & (4.6 -2)/2 = 1.3 cm height
2 cm & 4.6 cm parallel Side & (20.6 -16.4)/2 = 2.1 cm height
Area = (1/2)(16.4 + 20.6) * 1.3 = 24.05 cm²
Area covered by 2 = 2 * 24.05 = 48.1 cm²
Area = (1/2)(2 + 4.6)* 2.1 = 6.93 cm²
Area covered by 2 = 2 * 6.93 = 13.86 cm²
Total Area covered = 48.1 + 13.86 = 61.96 cm²
Learn more:
Find the area of trapezium in which parallel sides are of length 5 cm ...
https://brainly.in/question/3877026
There is a trapezium whose parallel sides are 10 cm and 22.3 CM ...
https://brainly.in/question/6716688
Answer:
Step-by-step explanation:
We need to get area covered by all trapezium
then Area = 20.6 * 4.6 - 16.4 * 2
= 94.76 - 32.8
= 61.96 cm²
if We found area of trapezium one by one
Sizes of two Trapezium are
16.4 & 20.6 cm parallel Side & (4.6 -2)/2 = 1.3 cm height
2 cm & 4.6 cm parallel Side & (20.6 -16.4)/2 = 2.1 cm height
Area = (1/2)(16.4 + 20.6) * 1.3 = 24.05 cm²
Area covered by 2 = 2 * 24.05 = 48.1 cm²
Area = (1/2)(2 + 4.6)* 2.1 = 6.93 cm²
Area covered by 2 = 2 * 6.93 = 13.86 cm²
Total Area covered = 48.1 + 13.86 = 61.96 cm²