Math, asked by nandana86, 1 year ago

A rectangle is to be made with perimeter 100m & area 525 square metres. what should be the length of its sides?

Answers

Answered by kamalmahipal
24
Here is your answer dear friend,
====================
Area = 525m²
length x Breadth = 525
lxB = 525-----------------(1)

perimeter= 100m
2(l+B) = 100
l+B = 50
l = 50-B--------------------(2)

putting (2) in (1)
(50-B) B = 525
50B - B² = 525
0= B² -50B +525
0= B² -35B -15B +525
0 = B(B-35) -15(B-35)
0= (B-15)(B-35)
so,
B= 15 or 35
L = 35 or 15
so, the pair of sides can be=(15,35) (35,15)
=====================
Hope this will help you and please mark as brainlist answer and follow for such more solutions.

kamalmahipal: plz follow and mark as brainlist
nandana86: Sorry , there is no column for mark you as brainlist. so I can't
nandana86: plz follow me
nandana86: from 0=B^2 - 35B - 15B + 525. where do you get 35 &15
kamalmahipal: after this step I did middle term split and then put the factors equal to zero
nandana86: it also can be 25 & 25
Similar questions