Question

A rectangle is trice as long as it is wide.if its width is 8 one upone 3cm find the area of rectangle???

Answer 1

Answer:

208.33 sq. cm. {Approximately}.

Step-by-step explanation:

Let the Breadth of the Rectangle be: x.

Lenght of the Rectangle: 3x.

But, given is the Breadth: 8 1/3 cm.

→25/3 cm.

Lenght: 3x = 3 × 25/3

→25 cm.

Area of the Rectangle: (l×b) unit

→(25 × 25/3)

→625/3

→208.3 3 sq. cm.

Hence, the area of the Rectangle is 208.33 sq. cm.{Approximately}.

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Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\pink{Given:-}}$

$\sf \bullet length\:of\: rectangle=3\times its\: breadth\\ \\ \sf\bullet Breadth\:of\: rectangle=8\dfrac{1}{3} \\ \\ \sf\:\:\implies Breadth =\dfrac{25}{3}cm$

$\sf\underline{\purple{ Solution:-}}$

• Now first find the length of rectangle

$\sf\implies length\:of\: rectangle=3\times breadth\\ \\ \sf\implies length=3\times 8\dfrac{1}{3}\\ \\ \sf\implies length=\cancel3\times \dfrac{25}{\cancel3}\\ \\ \sf\implies length=25cm$

Then:- Area

$\boxed{\sf{Area\:of\: rectangle=l\times b}}$

$\bold{Given}\begin{cases}\sf{Length=25cm}\\ \sf{Breadth=\dfrac{25}{3}cm}\end{cases}$

$\sf :\implies Area\:of\: rectangle=25\times \dfrac{25}{3}\\ \\ \sf :\implies Area=\dfrac{25\times 25}{3}\\ \\ \sf\implies Area=\cancel{\dfrac{625}{3}}\\ \\ \sf\implies {\blue{Area=208.33cm{}^{2}}}\:\:(approx...)$

$\boxed{\sf{\red{Area\:Of\: Rectangle=208.33cm{}^{2}}}}$