Question

a rectangle is twice as long as it is wide and it has perimeter of 42 cm. find its lenght and width. ( By comparison method)​

Answer 1

$\huge{ \underline{ \underline{ \green{ \sf{ SoLuTiOn :- }}}}}$

Let the width of a rectangle is x .

Then , the length of a rectangle be 2x .

We know that :-

${\purple{\boxed{\large{\bold{</u><u>P</u><u>erimeter \: = 2(l + b)}}}}}$

According to question :-

2(2x+ x ) = 42

=> 4x + 2x = 42

=> 6x = 42

=> x = 42/6

=> x = 7

Putting x = 7

Then , length = 2x = 2×7 = 14

${\blue{\boxed{\large{\bold{Length = 14 cm \: and \: width = 7 cm }}}}}$