Question

a rectangle measures 5 cm on its breadth its diagnal is 13cm find its perimeter

Answer 1

According to hypotenuse theory H^2=B^2+A^2
We can find length of the rectangle as √13^2-5^2=(13×13-5×5)=√169-25=√144=12
As the length is 12 and the breadth is 5 the perimeter of rectangle is 2(l+b)=2(12+5)=2×17=34

I hope this answer is correct.

Answer 2

In rectangle ABCD
AB=5
Ac=13
by using Pythagoras
13*13=(5*5)+BC*BC
169=25+BC*BC
BC*BC=169-25
BC*BC=144
BC=12cm
by using formula of perimeter of rectangle
P=2(l+b)
P=2(5+12)
P=2*17
P=34cm