If x= 2(√2+√6)/3√(2+√3), then x is equal to-- a)4/3 b)16/9 c)2/3 d)3/4
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Answered by
29
x=2 (root2+root6)/3root (2+root3)
3x.root (2+root3)= 2 (root2+root6)
take square both side
9x^2. (2+root3) =4 (root2+root6)^2
9x^2 (2+root3)=4 (8+4root3)
9x^2 (2+root3)=16 (2+root3)
9x^2 = 16
x^2 =16/9
take square root both side
x=+_4/3
hence option (a) is correct .
3x.root (2+root3)= 2 (root2+root6)
take square both side
9x^2. (2+root3) =4 (root2+root6)^2
9x^2 (2+root3)=4 (8+4root3)
9x^2 (2+root3)=16 (2+root3)
9x^2 = 16
x^2 =16/9
take square root both side
x=+_4/3
hence option (a) is correct .
Answered by
9
Step-by-step explanation:
X=2(√2+√6)/3(√2+√3)
3X(√2+√3)=2(√2+√6)
squaring both sides
9X²(2+√3)=4(8+4√3)
9X²(2+√3)=16(2+√3)
(2+√3) is on both side, that's why it is canceled
then we get,
9X²=16
X²=16/9
(X)²=(16/9)²
X=4/3
So, last option is correct
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