Question

A rectangle of length 50 m and width 30 m was to be fenced along the boundaries. Find the perimeter of another rectangle of twice the length and half the width of the given rectangle.​

Answer 1

Answer:

230m

Step-by-step explanation:

New Length: 50×2 m =100m

New Width: 30/2 m =15m

Perimeter of another rectangle : 2(100+15)m = 230m.

Answer 2

Answer:

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Step-by-step explanation:

L = 50m B = 30m

length 1=2x50 breadth=1/2x30

perimeter = 2(100+15)

=230m

Hope it helps uh ♡

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