Question

a rectangle plot is fenced with 150 long wire.find the dimension of the plot if its lenght is twice its breadth

Answer 1

$\textbf {Hey there, here is the solution.}$

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let the width be x

Length = 2x

Form the equation:

Perimeter = 2(Length + Breadth)

150 = 2( x + 2x)

Solve x:

150 = 2( x + 2x)

Distribute 2:

150 = 2x + 4x

Combine like terms:

150 = 6x

Switch sides:

6x =150

Divide both sides by 6:

x = 25

Find the length and breadth:

Breadth = x = 25 units

Length = 2x = 2(25) = 50 units

Answer: The length is 50 units and the breadth is 25 units.

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⭐$\textbf {Cheers}$⭐

Answer 2

$\bf \large \it{Hey \: User!!!}$

according to the question, the length is twice it's breadth.

let the breadth of the rectangle be x.

therefore it's length = 2x

the rectangular plot is fenced with 150 long wire. hence it's perimeter is 150 unit.

therefore 2 ( l + b ) = 150m
>> 2 ( 2x + 3x ) = 150m
>> 5x = 150/2
>> 5x = 75
>> x = 75/5
>> x = 15

hence, breadth of the rectangular plot = x = 15 units

and length of the rectangular plot = 2x = 2 × 15 = 30 units

$\bf \large \it{Cheers!!}$