Math, asked by Anonymous, 7 months ago

A rectangle room is 10 m long and 6m wide find the cost of covering the floor with a carpet 2m wide at the rate of ₹ 42 per metre​

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Answered by fatimasidra
4

Answer:

Cost of covering the whole floor = ₹1260

Step-by-step explanation:

First of all, we have to find the area of the floor. Then we have to find the cost of carpet for covering the floor.

Here, length of the floor is 10 m.

         & breadth is 6 m.

Therefore, area of the floor = l×b

                                                = 10 m × 6 m

                                                = 60 m²

Area of room = Area of carpet.

Thus, 60 m² = Length of carpet × Breadth of carpet

          60 m² = Length of carpet × 2 m

          \frac{60 m^{2} }{2 m} }  = 30 m = Length of the carpet.

Cost of covering the floor of 1 m = ₹42

Therefore, cost of covering the whole floor = ₹42×30  m

                                                                           = ₹1260

Answered by shubhamyadavy825
1

Answer:

area of the floor = l×b

= 10 m × 6 m

= 60 mArea of room = Area of carpet.

Thus, 60 m² = Length of carpet × Breadth of carpet

60 m² = Length of carpet × 2 mCost of covering the floor of 1 m = ₹42cost of covering the whole floor = ₹42×30 m

= ₹1260

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