Math, asked by priyambhattacharya73, 5 months ago

A rectangle tank of dimensions 24m by 12m by 8m is dug inside a rectangular field 600m long and 200m broad. The earth taken out is evenly spread over the field. By how much will the level of the field rise?​

Answers

Answered by kavya164
5

Answer:

he filed will rise up to a level of 1.92 cm.

Step-by-step explanation:

Length of the rectangular field = 600 m

Breadth of the rectangular filed = 200 m

∴ The area of the rectangular field = Length x Breadth = 600 * 200 = 120000 mFor the rectangular tank:

Length = 24 m

Breadth = 12 m

Height = 8 m

∴ The area of the base of the tank = l * b = 24 * 12 = 288 m²

 ∴ The area of the rectangular field excluding the tank is given by,

= [The area of the rectangular field] – [The area of the base of the tank]

= 120000 – 288

= 11Now, it is given that the amount of earth taken was used to level the rectangular field, so

Therefore, we can write  

24*12*8 = 119712 * [Rise in level of field]

⇒ 2304 = 119712 * [Rise in level of field]9712 m²²

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