A rectangle was altered by increasing its length by 10 percent and decreasing its width by p percent. If these alterations decreased the area of the rectangle by 12 percent, what is the value of p?
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Ans : 20
Area of rectangle = Length × Breadth
Let A1 = L1 × B1
Given , L2 = 10 % + L1 = 1.1 L1
And, B2 = B1 - P/100 = 100B1 - P/100
➡️ A2 = 0 . 88A1
➡️ L2 × B2 = 0.88 ( L1 × B1 )
➡️ 1.1L1 × B1 - P/ = 0.88 ( L1 × B1 )
➡️ 1.1 × ( B1 - P ) = 88 B1
➡️ 110 B1 - 1.1 P = 88 B1
➡️ 22 B1 = 1.1 p
➡️ •°• P = 20
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