write four solutions of an a equation 2x+2y = 2
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Answered by
0
Answer:
Answer
Given equation is:
2x+y=7
For x = - 1, we get
−2+y=7
⇒y=9
∴ (-1, 9) is a solution.
For x = 0, we get
⇒0+y=7
⇒y=7
∴ (0, 7) is a solution.
For x = 1, we get
⇒2+y=7
⇒y=5
∴ (1, 5) is a solution.
For x = 2, we get
⇒4+y=7
⇒y=3
∴ (2, 3) is a solution.
Hence, we have four solution (−1,9),(0,7),(1,5)and(2,3)
Hope it helps!!!
Answered by
1
Answer:
2x-2y=2 -------->(i)
2x=2+2y
x = 2+2y/2 ----------> (ii)
from equation (i) and (ii)
2[2+2y/2] - 2y = 2
4 + 4y - 2y = 2
4 + 2y = 2
2y = 2 - 4
2y = -2
y = -2/2
y = -1
Now, Put the value of y in equation (ii)
x = 2+2(-1)/2
x = 2-2/2
x = 0/2
x = 0
Therefore,
x = 0 and y = -1
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