A rectangle whose perimeter is 266m,has width that is 5m shorter than its length . what are the dimensions of the rectangle
Answers
Answered by
4
Answer.
Perimeter is 266
Let length be b
Acc to que
b=l-5
2(l+l-5)
4l-10=266
4l=276
L=69
B= 69-5 =64.
Hope it will help you
And breadth be
Step-by-step explanation:
Answered by
1
Answer:
length = 69
width = 64
Step-by-step explanation:
given
perimeter= 266m
let length = x
width = x-5
perimeter= 2 ( l+b)
266 = 2× ( 2x- 5)
266 = 4x - 10
276/4 = x
69= x
length ( x)= 69
width (x-5) = 69-5
= 64
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