Math, asked by s55273, 4 months ago

A rectangle with length 8 yards. The area of the rectangle is marked as 48 square yards. Find the perimeter of the rectangle.

Answers

Answered by bharat212003
1

Answer:

length=8

area=l×b=8×X

48=8x

48/8=x

x=6

therefore, perimeter=2(l+b)

=2(8+6)

=28yards

Answered by sb93
0

Answer:

28 yards

Step-by-step explanation:

Data:

  • A = 48 square yards
  • l = 8 yards
  • b = ?
  • p = ?

Solution:

\implies \sf{b = {\Large\frac{A}{l}} }

\implies \sf{ {\Large\frac{48 } { 8} }}

\therefore \sf{b = 6\ yards }

Now to find perimeter:

\implies \sf{Perimeter\ = 2(l+b) }

\implies \sf{2(8+6) }

\implies \sf{2(14) }

\implies \sf{ 28\ yards}

\therefore \boxed{\sf{Perimeter\ = 28\ yards  }}

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