A rectangle with perimeter 104 cm has a width of 18 cm less that its length. What is the area?
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Answer:
8944
Step-by-step explanation:
104-18=86 104(86)=8944
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Let the length of the rectangle be X
A.T.Q
Width of the rectangle = X-18
Perimeter of rectangle= 2(l+b)
2(x+x-18)= 104
2x+2x-36= 104
4x= 104+36
4x= 140
x= 140/4
x=70
x-18
70-18 = 52
length of the rectangle = 70cm
width of the rectangle = 52cm
Area of rectangle = l*b
70*52 = 3640cm^2
ANSWER
A.T.Q
Width of the rectangle = X-18
Perimeter of rectangle= 2(l+b)
2(x+x-18)= 104
2x+2x-36= 104
4x= 104+36
4x= 140
x= 140/4
x=70
x-18
70-18 = 52
length of the rectangle = 70cm
width of the rectangle = 52cm
Area of rectangle = l*b
70*52 = 3640cm^2
ANSWER
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